Question

1.
Find the zeroes of the polynomial P ( x ) = x^2 - 3.​

Answer 1

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Given

p(x) = x² - 3

For zeroes of the p(x)

=> x² - 3 = 0

=> (x)² - (√3)² = 0

=> (x-√3) (x+ √3) = 0

=> x = +√3 and x = -√3

Answer 2

Step-by-step explanation: x^2-3=0

x^2 =3

x = + or - √3

X =√3 or X= -√3