Question

1) Find the zeros of the polynomial p(x)=x2-2x-8​

Answer 1

Answer:

$x {}^{2} - 2x - 8 = 0$

$x {}^{2} - (4 - 2)x - 8 = 0$

$x {}^{2} - 4x + 2x - 8 = 0$

$x(x - 4) + 2(x - 4) = 0$

$(x - 4)(x + 2) = 0$

$either$

$x = 4$

$or$

$x = - 2$

Answer 2

Answer:

p(x)=3x5-15x4-12x3+8x2+7x-10