Question

《1》Five years ago a man was seven times as old as his son. Five years hence,
three times as old as his son. Find their present ages.

Plz show working .... i need it fast.​

Answer 1

Answer:-

Present age of Son = 10 years

Present age of father = 40 years

Solution:-

Let five years ago the age of Son be X years and age of father be 7x years.

Then, A/Q,

present age of son = x + 5

present age of father = 7x + 5

Then,

5 years later the age will be x + 10 and 7x + 10

Therefore,

7x + 10 = 3( x + 10 )

7x - 3x = 20

4x = 20

x = 5

So,

The present age of Son = x + 5 = 10 years

and,

The present age of father = 7x + 5 = 40 Years.

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