Question

1. For the hypothetical reactions, the equilibrium constant (k) values are
given
A=B: k, = 2
B=C: K2 = 4
C=D:K3 = 8
The equilibrium constant (K) for the reaction A=D is
(2) 48 (6) 24 (c) 12 (d) 64

(This sign '=' here is to represent reversible reaction.)​

Answer 1

Answer:

64

Explanation:

For reaction, AB, K=B/A

For reaction, BC, K=C/B

THEREFORE ADDING BOTH REACTIONS,

IE., A+B=B+C, K'=BC/AB=>C/A=2*4=8

Similarly for reaction A+C=C+D,

K''=CD/AC=K' *K3=8*8=64