1. For what distance is ray optics a good approximation when the aperture is 500 nm?
a) 22m
b) 32m
c) 42m
d) 52m
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Answer:32m
Explanation:Aperture Width a=4mm
Fresnel distance, Z
F
=
λ
a
2
=
500×10
−9
(4×10
−3
)
2
∴z
p
=32m
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