Math, asked by vipin1691, 1 year ago

1. For what value of k: k+2, (4k - 6), 3k - 2 are three consecutive terms of an Arithmetic progression.

Answers

Answered by mansigupta23

1

k+2,4k-6,3k-2 are in AP
2(4k-6)=k+2+3k-2
8k-12=4k
8k-4k=12
4k=12
k=3

mansigupta23: please mark me as a brainlist

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