Question

1. For what values of x will y be maximum or minimum!
y=x+1/x,x>0​

Answer 1

Answer:

we need to differentiate the equation first

Explanation:

dy/dx=d(x+1/x)/dx

=> [x.d(x+1) – (x+1)dx]/x²

=> [x –x–1]/x²

=> –1/x²

for max or min value dy/dx=0

=> –1/x² =0

=> 1/x =0 :. x––>infinity