Question

X^2-X+3 find the polynomial for 2alpha and 2 beta

Answer 1

Step-by-step explanation:

see first find roots from given quadratic polynomial , x²-3x+2=0=x²-x-2x+2=0=x(x-1)-2(x-1)=0(x-1)(x-2)=0x=1 or ,x=2 given zeroes of quadratic polynomial 1/2alpha+beta ,1/2beta+alpha substitute=1/2(1)+2, 1/2(2)+1=1/4,1/5formula is x²-(alpha+beta)x+alpha*beta =0therefore x²-(1/4+1/5)x+1/4*1/5=0=ans is 20x^2 - 9x +1 =0

I don't know its correct or wrong

HOPE IT IS HELPFUL