Question

1. Force of attraction between two point charges placed in air at a
distance r from each other is F. If these charges are placed in water
with same separation between them, then the force of attraction
between them is (K=80)
(1)F
(2)80F
(3)F/80
(4)zero

Answer 1

F=kq1q2/r*2

K=1/4π€€•

Answer 2

Concept introduction:

The force of attraction is a force that attracts the body closer together. In nature, there are several attracting forces at work. Magnetic force, electromagnetic force, electrostatic force, and gravitational force are a few of them.

Given:

Here it is given that Force of attraction between two point charges placed in air at a distance $r$ from each other is $F$.

To find:

We have to find the force of attraction.

Solution:

According to the question,

$\frac{F_1}{F_2} =80\\\frac{F_1}{80}=F_2$

then the force of attraction between them is  $\frac{F}{80}$.

Final answer:

So, the final answer of the question is $\frac{F}{80}$.

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