1. From the following figure,
find :
(I) y
(ii) sin x
(iii) (sec xº - tan x°) (sec xº + tan xº)
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3
Answer:
(i)y = √3 , (ii)sin x = √3 /2 (iii) (sec x° - tan x °)(sec x ° + tan x ° ) = sec ^2 x° - tan ^2 x° = 1
Answered by
2
Answer:
1)let the sides of the triangle be ABC
BY,P.T,
AB=AC+B.C.
-BC=AC-AN
-BC=1-2
-BC= -1
BC= 1
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