Question

1 g of magnesium is burnt with o.56 g O2 in a closed vessel . which reactant left in excess and how much

Answer 1

First of all write a balance Rxn

2Mg +o2 →→2 Mgo

Now 2 moles of mg react with 1 mole of oxygen

32 gm oxygen react with 48 gm of mg

Apply unitary method

32 gm o2 …….reacts with 48 gm mg

1gm of o2 will react ……..48／32

So,0.56 gm o2 will react ……..48×0.56/32

=0.84 gm magnesium .

This is the amount of mg that have been consume or react with oxygen …..so ,left amount

1–0.84=0.16 gm

I Hope this will help u ...

Answer 2

Answer:

First of all write a balance Rxn

2Mg +O2 → 2 MgO

Now 2 moles of mg react with 1 mole of oxygen

32 gm O2 react with 48 gm of Mg

Apply unitary method

32 gm O2 …….reacts with 48 gm Mg

1gm of O2 will react ……..48／32

So,0.56 gm O2 will react ……..48×0.56/32

=0.84 gm Mg.

This is the amount of mg that have been consume or react with oxygen …..so ,left amount

1–0.84=0.16

I Hope this will help u ..☺☺☺☺☺