Question

1. Given the following equation:

Zinc+ Hydro bromic acid----Zinc bromide + Hydrogen

i) Write the skeletal and balanced equation.

ii) Name the reactants and products involved in the reaction.

iii)What type of reaction it is? Explain.​

Answer 1

Explanation:

Given -

• Zinc+ Hydrobromic acid ⟶ Zinc bromide + Hydrogen

To Find -

1. Write the skeletal and balanced equation
2. Name the reactant and products involved in the reaction.
3. what type of reaction it is ? Explain.

1)

When zinc reacts with hydrobromic acid then it forms zinc bromide and realeses hydrogen gas.

Chemical equation :-

• Zn + 2HBr ⟶ ZnBr2 + H2↑

2)

Reactant :-

Name Formula state

Zinc (Zn) (s)

Hydrobromic acid (HBr) (aq.)

Product :-

Name Formula state

Zinc bromide (ZnBr2) (aq.)

Hydrogen gas (H2) (g)

3)

This is the example of Displacement reaction here displacement reaction take place because zinc (Zn) is more reactive than hydrogen.

Answer 2

Given reaction is :

Zinc + Hydro Bromic Acid -------> Zinc Bromide + Hydrogen.

______________________

First of all skeletal equation is :

$\sf{Zn\ +\ HBr\ \to\ ZnBr_2 + H_2}$

Now, we've to balance this equation

$\sf{Zn\ +\ 2HBr\ \to\ ZnBr_2\ +\ H_2}$

______________________

Elements or compounds which are in left side of reaction are called as reactants. Whereas elements or compounds on right side of arrow are known as products.

So, here.

Reactants : Zn (Zinc), 2HBr (Hydro Bromic Acid)

Products : ZnBr2 (Zinc Bromide) , H2 (Hydrogen)

__________________________

This reaction is displacement reactions, because Hydrogen is replaced by zinc. Because zinc is more reactive than hydrogen.