Question

Molecules 22.4 cm3 of nitrogen gas at STP is

Answer 1

Answer:-

There are 6.022*10^23 molecules present in 22400cm^3 gas.?  

Therefore the no. of molecules present in 22.4cm^3=?  

6.022*10^23 * 22.4cm^3 divide by:?  

224000 cm^3?  

Hence we get the ans as 6.022*10^20 molecules. Hope it helps..