1. Hari is twice as old as his son. Twenty
years ago, he was four times as old as his
son. Find their present age.
Answers
✬ Hari = 60 Years ✬
✬ Son = 30 Years ✬
Given:
- Hari is twice as old as his son.
- Twenty years ago he was four times as old his son.
To Find:
- What are their present ages ?
Solution: Let the present age of son be x years. Therefore,
➼ Hari's age = 2 times of x
➼ Hari's age = 2x years
[ Now, 20 years ago their ages were ]
- Son's age = (x – 20) years
- Hari's age = (2x – 20) years
A/q
- Twenty years ago hari was four times as old his son.
(2x – 20) = 4(x – 20)
2x – 20 = 4x – 80
– 20 + 80 = 4x – 2x
60 = 2x
60/2 = x
30 = x
So, present ages of
➙ Son is x = 30 Years
➙ Hari is 2x = 2(30) = 60 Years
Given :-
♦Hari is twice as old as his son
♦Twenty
years ago, he was four times as old as his
son.
To find :-
Present age of Father and son.
Solution :-
♦Let the present age of Hari be x yrs
♦And present age of son be y yrs
ATQ,
x = 2y --------------------(i)
20 yrs ago,
Hari's age = (x-20) yrs
Son's age = (y-20) yrs
=> (x-20) = 4(y-20)
=> x-20 = 4y-80
Putting the value of x
2y-20 = 4y-80
=> 2y-4y = -80+20
=> -2y = -60
=> 2y = 60
=> y = 30
x = 2y
= 2×30
= 60
Hence ,
=> Hari's age = 60
Son's age = 30
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