Question

(1+i)(1-I)^-1 find a and b in the form of a+ib​

Answer 1

Answer:

(1+i)/(1-i)

=(1+i)^2/(1-i^2)

=(1+i^2+2i)/(1+1) where i^2=-1

=(1-1+2i)/2

2i/2=i=0+1(i)=a+ib

a=0, b=1