{(1+i)/(1-i)}^2 please answer it
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Step-by-step explanation:
{(1+i)/(1-i)}²
= (1+i²+2i)/(1+i²-2i)
= (i²+2i+1)/(i²-2i+1)
= (i²+i+i+1)/(i²-i-i+1)
= {i(i+1)+1(i+1)}/{i(i-1)-i(i-1)}
= {(i+1)(i+1)}/{(i-1)(i-1)}
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