Question

{(1+i)/(1-i)}^2 please answer it​

Answer 1

Step-by-step explanation:

{(1+i)/(1-i)}²

= (1+i²+2i)/(1+i²-2i)

= (i²+2i+1)/(i²-2i+1)

= (i²+i+i+1)/(i²-i-i+1)

= {i(i+1)+1(i+1)}/{i(i-1)-i(i-1)}

= {(i+1)(i+1)}/{(i-1)(i-1)}

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