Math, asked by golu1951, 1 year ago

solve for x. x^2-(√3+1)x+√3=0​

Answers

Answered by syedali8
2

Step-by-step explanation:

Step by step solution :

Step 1 :

Equation at the end of step 1 :

3

((x2)-((2•—)•x))+3 = 0

2

Step 2 :

3

Simplify —

2

Equation at the end of step 2 :

3

((x2) - ((2 • —) • x)) + 3 = 0

2

Step 3 :

Trying to factor by splitting the middle term

3.1 Factoring x2-3x+3

The first term is, x2 its coefficient is 1 .

The middle term is, -3x its coefficient is -3 .

The last term, "the constant", is +3

Step-1 : Multiply the coefficient of the first term by the constant 1 • 3 = 3

Step-2 : Find two factors of 3 whose sum equals the coefficient of the middle term, which is -3 .

-3 + -1 = -4

-1 + -3 = -4

1 + 3 = 4

3 + 1 = 4

Answered by nova5
10

hey \: mate \: thank \: for \: the \: question \:  \\ hope \: it \: helps \\  =  > x {}^{2}  - ( \sqrt{3}  + 1)x +  \sqrt{3}  \\  =  > x {}^{2} -  \sqrt{ 3}x - x +  \sqrt{3}   \\  =  > x(x -  \sqrt{3}) - 1(x -  \sqrt{  3}) \\  =  > (x - 1)(x -  \sqrt{3}) \\  x - 1 = 0  \\ x = 1 \:  \:  \:  \:  \:  \:  \:  \:  \: x -  \sqrt{3 } = 0 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x =  \sqrt{3}

Similar questions