(1-i/1+i)^96 in a+ib form
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means I don't understand your question
sbch57:
sorry this is not the question , c now my second question
it's okay
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(1-i)(1-i)/(1-i)(1-i)=1-i^2-2i/1+1
1-1-2i/2
-i^96. =1=1+0i
sorry this is not my question c the second question
answer is 1+0i
no its not there r options pls check it out
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