Question

1-i√3/2+2i findthe modulus

Answer 1

1-i$\sqrt{3}$ / 2+2i

=$\frac{1-\sqrt{3} }{2+2i } *\frac{2-2i}{2-2i}</strong></p><p><strong>=[tex]=\frac{2-2i+2i\sqrt{3}+2 }{4-(-4)} \\=\frac{4+2i(-1+\sqrt{3} }{8}$

4/8 +2i($\sqrt{3}$-1)/8

1/2+1/8*i($\sqrt{3}$-1)

x=1/2 and y=1/8*i($\sqrt{3}$-1)