Question

(1-i)^3 is in complex numbers
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Answer 1

Answer:

-2 ( 1 + i )

Step-by-step explanation:

${(x + y)}^{3} = {x}^{3} - {y}^{3} - 3 {x}^{2} y + 3x {y}^{2} \\ \\ {i}^{2} = - 1 \\ \\ {(1 - i)}^{3} = 1 - {i}^{2} i - 3i + 3 {i}^{2} \\ \\ = 1 + i - 3i - 3 \\ \\ = - 2(1 + i)$

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