Question

(1+i)^-3 State the values of a & b where it is in the form a+ib​

Answer 1

Answer:

1)

(1+2i)(-2+i)

= -2 + i - 4i + i²

= -2 - 3i - 1

= -3 - 3i

Here

a = -3 and b = -3

2)

(1+i)(1-1)-1i(4 + 3i)(2 +i)

= (1 + i)(0) - 1i(4 + 3i)(2 +i)

= 0 - 1i(4 + 3i)(2 + i)

= -1i(4 + 3i)(2 + i) = (3 - 4i)(2+ i)

= 6 + 3i - 8i - 4i²

= 6 - 5i + 4

= 10  - 5i

Here

a = 10     and    b = -5

3)

(1i) (3+2i)(3-2i)

= (i)(3² - i²)

= i(9 + 1)

= 10i = 0 + 10i

Here

a = 0   and b = 10

4)

 (3-1)(1+2i)

= 3 + 6i - 1 - 2i

= 2 + 4i

Here

a = 2   and   b = 4

5)

21 V-3

= 21√3√-1

= (21√3)i            ∵ √(-1) = i

= 0 + (21√3)i  

Here

a = 0   and   b = (21√3)

Do in the same way others

Step-by-step explanation: