Question

(1+i)^5×(1-i)^5
where i stands for iota in complex no

Answer 1

Hiii...

Answer is 32 .....

Answer 2

given : (1+i)^5×(1-i)^5
={(1+i)(1-i)}^5

We know that (i)² = -1

Hence (1²-i²)^5 {using (a-b)(a+b) = a²-b²
=> (1-(-1)^5
= 2^5
= 32