1. I am a two-digit number. My tens digit
is 4 more than my ones digit. If you
multiply me by 5, the estimated
product is 300. What number
am I?
Answers
Answered by
3
the answer is fifteen(15)
rohan6954:
i don't think that its a right ans.
Answered by
6
let the tens digit number be10x
then, the ones digit number be y
case1
the tens digit is 4 more then it's one digit
so , 10x=4+y. (equation 1)
case2
the number is (10x+y). {eg.10×6+5=65}
(10x+y)5=300. (equation 2)
taking value of 10x from eq.1 and putting in eq2
(10x+y)5=300
4+y+y=300÷5
4+2y=60
2y=60-4
y=56÷2
y=28
10x=4+y
10x=4+28
x=32÷10
x=3.2
so, the number is 10x+y=10×3.2 + 28
32+28=60
your answer is 60
then, the ones digit number be y
case1
the tens digit is 4 more then it's one digit
so , 10x=4+y. (equation 1)
case2
the number is (10x+y). {eg.10×6+5=65}
(10x+y)5=300. (equation 2)
taking value of 10x from eq.1 and putting in eq2
(10x+y)5=300
4+y+y=300÷5
4+2y=60
2y=60-4
y=56÷2
y=28
10x=4+y
10x=4+28
x=32÷10
x=3.2
so, the number is 10x+y=10×3.2 + 28
32+28=60
your answer is 60
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