1. I have total of Rs 300 in coins of denomination Re 1,Rs 2 and Rs 5. The number of Rs 2 coins is 3 times the number of Rs 5 coins. The total number of coins is 160. How many coins of each denomination are with me
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We can assume 1x + 2y +5z= 300 ---> (1)
Total no.of coins , x+y+z = 160 --->(2)
y=3z -->(3)
Subtituting value of (3) in (1) and (2)
1x + (2) * 3z + 5z= 300
ie; 1x + 6z+5z=300 = x + 11z=300 --> (3)
x+3z+z=160 --> (4)
Considering eqn (3) and (4)
x+11z=300
x+4z=160
then 7z=140 as x cancelled each other.
then z= 20
Now we can calculate rest...
z=20
y = 3z = 60
x+2y+5z=300
then x = 300 -120-100
= 80
x = 80
y=60
z=20
Solved...
Total no.of coins , x+y+z = 160 --->(2)
y=3z -->(3)
Subtituting value of (3) in (1) and (2)
1x + (2) * 3z + 5z= 300
ie; 1x + 6z+5z=300 = x + 11z=300 --> (3)
x+3z+z=160 --> (4)
Considering eqn (3) and (4)
x+11z=300
x+4z=160
then 7z=140 as x cancelled each other.
then z= 20
Now we can calculate rest...
z=20
y = 3z = 60
x+2y+5z=300
then x = 300 -120-100
= 80
x = 80
y=60
z=20
Solved...
Answered by
0
Answer:
Answer : x=80, y=60 & z=20
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