1+ i power 2n+1/1+i power 2n-1 find the conjugate answer within 5 mins
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Hey there !!!!!!!!!!!
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=(1+i)²ⁿ⁺¹/(1-i)²ⁿ⁻¹
Using aⁿ⁺ˣ=aⁿ*aˣ
=(1+i)²ⁿ*(1+i)/(1+i)²ⁿ*(1+i)⁻¹
=(1+i)/(1+i)⁻¹
Using aⁿ/aˣ=aⁿ⁻ˣ
=(1+i)¹⁻⁽⁻¹⁾=(1+i)² =1²+2i+i²
But i²=-1
(1+i)² =1+2i-1
=2i
Conjugate of 2i is -2i
∴ Conjugate of (1+i)²ⁿ⁺¹/(1-i)²ⁿ⁻¹ is -2i.
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Hope this helped you..............
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
=(1+i)²ⁿ⁺¹/(1-i)²ⁿ⁻¹
Using aⁿ⁺ˣ=aⁿ*aˣ
=(1+i)²ⁿ*(1+i)/(1+i)²ⁿ*(1+i)⁻¹
=(1+i)/(1+i)⁻¹
Using aⁿ/aˣ=aⁿ⁻ˣ
=(1+i)¹⁻⁽⁻¹⁾=(1+i)² =1²+2i+i²
But i²=-1
(1+i)² =1+2i-1
=2i
Conjugate of 2i is -2i
∴ Conjugate of (1+i)²ⁿ⁺¹/(1-i)²ⁿ⁻¹ is -2i.
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Hope this helped you..............
divyanshbajaj11:
Wrong answer
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