1. (i)Two pendulums A and B have length 2 m and 0.5 m. Which pendulum will make more oscillations in one minute and why? (ii) What is the relation between time period (T) and frequency (f) of an oscillation of a simple pendulum?
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Answer:
Time period of
oscillation
of a simple pendulum
is given by:
T=2π√ l/g∝ √l
Thus, the ratio of their time periods is T1/T2 =√0.5/2
= 1/2
⟹T 2 =2T 1
Thus, the shorter
pendulum would have completed exactly 2 oscillations
when the longer pendulum would have completed the first oscillation.
Explanation:
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