Question

1-ialpha/1+ialpha=A+iB Then A^2+B^2 is

Answer 1

Answer:

It is given that

z=1+iα

Hence, z

2

=(1+iα)

2

=(1−α

2

)+i(2α) =x+iy

Hence, x=1−α

2

And y=2α

Thus

2

y

=α

Substituting in the equation of x gives us

x=1−(

2

y

)

2

x=1−

4

y

2

4x=4−y

2

y

2

+4x−4=0