Question

1.
If a = -5, b=-6, c = 10, then the value
a3 + b3 + c3-3abc
of
(ab+bc+ca-a? -b2-c?) :
(a) -1
Los 1
(c) 18
(d) 21
(b) -13​

Answer 1

answer is 21

a=15

b=18

c= 30

3abc=189