Math, asked by razimhd136, 5 days ago

1. If A, B and C are mutually exclusive and exhaustive events, then P(A) + P(B) + P(C) equals to: ​

Answers

Answered by biswashridayraj514
4

Answer:

Therefore we can write that \[P(A) + P(B) + P(C) = 1\] which makes option B to be the correct option here. Note: When two events are only mutually exclusive then only their probabilities are normally added then it can take any value from 0 to 1.

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Answered by gadsachin
1

Answer:

Given A,B,C are mutually exclusive and exhaustive events

When A,B,C are mutually exclusive events,

⇒P(A∪B∪C)=P(A)+P(B)+P(C)

When A,B,C are exheustive event,

⇒P(A)+P(B)+P(C)=1

Hence, the answer is probability always 1.

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