1. If A, B and C are mutually exclusive and exhaustive events, then P(A) + P(B) + P(C) equals to:
Answers
Answered by
4
Answer:
Therefore we can write that \[P(A) + P(B) + P(C) = 1\] which makes option B to be the correct option here. Note: When two events are only mutually exclusive then only their probabilities are normally added then it can take any value from 0 to 1.
plz mark me as brainliest
Answered by
1
Answer:
Given A,B,C are mutually exclusive and exhaustive events
When A,B,C are mutually exclusive events,
⇒P(A∪B∪C)=P(A)+P(B)+P(C)
When A,B,C are exheustive event,
⇒P(A)+P(B)+P(C)=1
Hence, the answer is probability always 1.
PLEASE MARK ME AS BRAINLIST
Similar questions