Question

1. If A + B + C = 180°, prove that i) sin 2A + sin 2B + sin 2C = 4 sin A sin B sin C
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Answer 1

Answer:

2.0second and attains a 8.0ms-¹ 2.it continue at this speed for a further 1.5second. Sketch a graph of speed against time Find(1)the acceleration in stage (a) (2)the acceleration in stage (b) (3)the total distance moved during stages (a)and(b)

Step-by-step explanation:

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Answer 2

Answer:

A+B+C=180

LHS=sin2A+sin2B+sin2C

=2sin(A+B)cos(A−B)+2sinCcosC

=2sinCcos(A−B)+2sinCcosC

=2sinC(cos(A−B)+cosC)

=2sinC(cos(A−B)−cos(A+B))

=2sinC2sinAsinB

=4sinAsinBsinC

=RHS