Question

1) if a wire is bent in the form of equilateral triangle its area is 49 root 3cm². find the area of square and rectangle with the same wire.​

Answer 1

Answer:

Area of an equilateral triangle=

4

3

a

2

where a=side of the triangle

Now, given that

4

3

a

2

=121

3

a

2

=121×4

a

2

=484

a=

484

a=22 cm

Therefore,

Length of wire=a+a+a=66 cm

Now, this wire is bent into a circle, so circumference of circle=length of the wire

So,

2πr=66

2×

7

22

×r=66

r=

2×22

66×7

r=

2

21

Now,

Area of circle=πr

2

=

7

22

×(

2

21

)

2

=

2

693

=346.5 cm

Answer 2

Step-by-step explanation:

area of the equilateral triangle is √3/4 side^2

√3/4side^2=49√3

side =√49.4=7.2=14

length of the wire is 3.14cm 42 cm

side of the square is 42/4cm=21/2cm

area of the square is 21×21/2×2cm^2

=441/4cm^2