Question

1)If Alfa,beta are the zeroes of the polynomial x^2-16,then alfa×beta(Alfa+beta) is
a)0
b)4
c)-4
d)16
2) If Alfa,beta,gamma are the zeroes of the cubic polynomial ax^3+bx^2+CX+d then alfa×beta+beta×gamma+alfa×gamma is equal to
a)-b/a
b)b/a
c)c/a
d)d/a
please any one answer me correct it is very important to me please
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Answer 1

Answer:

Hey mate!! Here is your answer..

Step-by-step explanation:

[ i ] Given..

Polynomial = x^2-16

Let the given polynomial be equal to zero..

So,.. x^2-16=0

• x^2=16
• x=+ or - √16
• x=4 or -4

Therefore alpha is equal to 4 and beta is equal to -4..

Alpha = 4..

Beta = -4..

By the given condition.. alpha x beta(alpha+beta) will be equal to..

= -4x4(4-4)

= -16(0)

= 0

So,.. "a" is the correct option..

[ ii ] Given ..

Polynomial = ax^3+bx^2+cx+d

So,.. alfa×beta+beta×gamma+alfa×gamma is equal to..

= c/a..

So,.. "c" is the correct option..

Hope this answer is helpful to you..