1) If an angle is 28⁰ less than its complement, find its measure.
2) If an angle is 30⁰ more than one half of its complement, find the measure of the
angle.
3) If the angles (2x-10)⁰ and (x-5)⁰ are complementary angles, find x.
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Answer:
1)Angle = 90°-28°=62°
2)Let the angle be x and its compliment be y such that x+y=90°. then y=90-x.
According to the question,
x= 30+y
x=30+ (90-x/2)
x=30+45-x/2
x-x/2=75
3x/2=75
3x=150
x=50
3)(2x-10)+(x-5)=90
3x-15=90
3x=105
x=35
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