Question

1) If liquid in A and C are mixed, find temperature of mixture.

[ Answer is 16°C ]​

Answer 1

Answer:

Calculate the final temperature of the water mixture using the equation T(final) = (m1_T1 + m2_T2) / (m1 + m2), where m1 and m2 are the weights of the water in the first and second containers, T1 is the temperature of the water in the first container and T2 is the temperature of the water in the second container.

Explanation:

Hope it helps you

Answer 2

Answer:

Some vital info of question is missing. So, the question is incorrect.

Explanation:

There should be mentioning of

• mass or
• mass and specific heat

⟡ If only mass is mentioned, then the final temperature T is

[If mass of A = m₁ and mass of C = m₂, Temperatures are T₁ and T₂ respectively, then, ]

$\boxed{\mathrm{T = \dfrac{m_1T_1 + m_2T_2}{m_1+m_2}}}$

⟡ If mass and specific heats are mentioned, then the final temperature T is

[If mass of A = m₁ and mass of C = m₂, Temperatures are T₁ and T₂ respectively, Specific heats are c₁ and c₂ respectively, then, ]

$\boxed{\mathrm{T = \dfrac{m_1c_1T_1 + m_2c_2T_2}{m_1c_1 + m_2c_2}}}$

• If all the masses are equal then,

$\implies \mathrm{T = \dfrac{mT_1 + mT_2}{m+m}}$

$\implies \mathrm{T = \dfrac{T_1 + T_2}{2}}$

Here, T1 = 10 and T2 = 40

So,

$\implies \mathrm{T = \dfrac{10 + 40}{2}}$

=> T =  50/2

=> T = 25°C

Hope it helps!!