Question

1. If log2x + log4x = 6, then the value of x is:
(a)16 (c) 64 (b)32 (d) 128

8. The value of log(1³+2³+3³+...n³) is equal to:
(a)3 log 1 + 3 log 2 + ….. + 3 log n (b)2 log n + 2 log (n + 1) – 2 log 2 (c)log n + log (n + 1) + log (2n + 1) – log 6 (d)1

Can anyone please answer the above two questions? Wrong answers will be reported. Thank you

Answer 1

Answer:

x = 10^3/2(2)^1/2

Step-by-step explanation:

(a) . log2x + log4x = 6

log8(x)^2 = 6

8(x)^2 = 10^6

x^2 = 10^6/8