Question

1)If n(A)=20,n(B)=28andn(A∪B)=36 then n(A∩B)=?

→n(A∪B)=n(A)+ ⎕-n(A∩B)

36=⎕+28-n(A∩B)

⎕ =48-n(A∩B)

∴n(A∩B)=48-36

∴n(A∩B)=⎕

​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

n(AUB) =n(A) +n(B) - n(A intersection B)

n(A intersection B) =12

Step-by-step explanation:

36=20+28-n(A intersection B)

So

n(A intersection B) =48-36

=12