1)If n(A)=20,n(B)=28andn(A∪B)=36 then n(A∩B)=?
→n(A∪B)=n(A)+ ⎕-n(A∩B)
36=⎕+28-n(A∩B)
⎕ =48-n(A∩B)
∴n(A∩B)=48-36
∴n(A∩B)=⎕
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Answered by
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Answered by
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Answer:
n(AUB) =n(A) +n(B) - n(A intersection B)
n(A intersection B) =12
Step-by-step explanation:
36=20+28-n(A intersection B)
So
n(A intersection B) =48-36
=12
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