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If O is the centre of the given circle and BC = AO, then:
solve with full prcs
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Answer:X=3y
Step-by-step explanation:
We know that BC=AO
So BC equal to radius of the given Circle.
Let's join OB
OB=AO (RADII OF SAME CIRCLE)
So BC=BO
∠BOC=∠BCO=y. [ They are corresponding to the equal sides of a triangle]
Then ∠OBC=180° −2y and OBA=2y [Exterior angle Property]
Then ∠OAB=∠OBA=2y. [ They are corresponding to the equal sides]
Then ∠AOB=180° −4y [because ∠AOB= 180°-(∠BAO+∠ABO) And ∠BAO=∠ABO=2y So 2y +2y = 4y]
∠AOC=180°−4y+y =180°-3y
And 180-(180-3y) = x [Linear pair axiom]
- 3y=X
- Your Ans.x=3y
Hope it helps.
Question was Very Interesting
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