Question

(1) if one of the angle of a parallelogram measure 75° ; find the other angle
(2) find the angels of a parallelogram ABCD in which < A= 2<B​

Answer 1

Answer:

1a)sum of complementary angles=90°

So, one angle=75°

=a+b=90°

=75°+b=90°

=b=90°-75°

So,b=25°.

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