Question

1. If sec 0- tan 0 1/3. thhen find the value of (sec 0 +tan 0).

0 means theta ​

Answer 1

$\tt sec\theta - tan\theta = \frac{1}{3} \\ \\ \tt We\:know\:that \\ \\ \tt {sec}^{2}\theta - {tan}^{2}\theta = 1 \\ \\ \tt \therefore (sec\theta - tan\theta)(sec\theta + tan\theta) = 1 \\ \\ \tt \therefore sec\theta + tan\theta = \frac{1}{sec\theta - tan\theta} \\ \\ \tt \therefore \boxed{\bold{\underline{\red{\tt sec\theta + tan\theta = 3 }}}}$

Answer 2

Answer:

Step-by-step explanation: