Question

1)
If sinc4/5 then find the value of

Cos 0 +tan0
2 Sec0​

Answer 1

Answer:

sin = 4/5 i,e p= 4, h= 5

To find base

According to Pythagoras,

p^2 = h^2 + b^2

(4)^2 = (5)^2 +b^2

16 = 25 + b^2

b^2 = 25-16

b^2 = 9

b^2 = (3)^2 ( from both side the square will be cut off)

b = 3

Now,

cosO + tanO X 2 X secO

=b/h + p/b X 2 X h/b

=3/5 + 4/3 X 2 X 5/3

=9 + 20/15 X 10/3

=29/15 X 10/3

=290/45

=58/9

HOPE YOU UNDERSTOOD!!