Question

1. If smallest division on the main scale of Verneir Calliperes 0.05cm and number of division
on the Vernier scale is 25. the LC of Vernier Callipers is ......
a) 0.0002 cm
b) 0.002 cm c) 0.001cm d) 0.01cm​

Answer 1

Answer:

option b is correct

Explanation:

least count of vernier =

minimum no. of div on main scale÷

total no. of division on vernier scale

= 0.05/25 = 0.002 cm

Answer 2

Given: smallest division on the main scale of Vernier Callipers = 0.05cm

number of divisions on the Vernier scale = 25

main scale reading (MSR)= 24

To Find: Least count -LC =?

Solution:

The least count is the smallest accurate measured value measured on an instrument's scale.

Formula used: 25 divisions on Vernier scale reading coincide with 24 divisions of the main scale divisions (MSD).

24 MSD = 25 VSD

1 VSD = 24/25 MSD

LC = (1MSD - 1VSD) × smallest division on main scale of Vernier scale

LC = [1 - 24/25] × 0.05

LC = [25 -24/25] × 0.5

LC = 1/25 × 0.5

LC = 1/50

LC = 0.02 cm

If 0.05mm is the smallest division on the main scale of Vernier Callipers, then LC = 0.002cm