Question

(1) If tana =5/6 tanß =1/11 then which of the following is true? (a) a + B = π radian /4 (b) a.ß = π radian/4 (c) α-ß =π radian/4 (d) a/B=π radian/4​

Answer 1

Answer:

Given tanA=65;tanB=111

Consider tan(A+B)=1−tanAtanBtanA+tanB

tan(A+B)=1−6511165+111

tan(A+B)=6666−56655+6

tan(A+B)=1

A+B=4π