Question

1. If the division of ax^3 + 9x^2 + 4x - 10 by (x+3) leaves a remainder 5, then find the value of 'a'.
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Answer 1

Answer:

Left f(x) = ax³+ 9x² + 4x - 10

X +3=0 ⇒ x= -3

On dividing f(x) by x + 3 , it leaves a remainder 5.

f(- 3) = 5

a(- 3)³+ 9 (- 3)² + 4(- 3) - 10 = 5

- 27a + 81 - 12 - 10 = 5

54 = 27a

a = 2

Answer 2

Step-by-step explation

Left f (x) = ax³ + 9x² + 4x - 10

x + 3 = 0 ---> x = -3

On dividing f (x) by x+3 it leaves a

remainder 5.

.

. . f(-3) =5

a (-3)³ 9 (-3)² + 4(-3) - 10 = 5

-27 a + 81 - 12 - 10 = 5

54 = 27a

a = 2

Explation:

Hope it will help you