Question

1. If the first term of an arithmetic progression is 6 and the 11th term is 76. What is the 5th term?​

Answer 1

Step-by-step explanation:

a1=6

a11=76

Now,

a1=

a+(n-1)d=6

a+(1-0)d=6

a=6. .........1

and a11=76

a+10d=76

6+10d=76. ( from 1)

10d=76-6

10d=70

d=70/10

d=7

therefore,

a5=a+4d

putting the values of a and d we get,

a5=6+4*7

=6+28

=34