Question

1 If two angles of a triangle are 410

and 480

.Find the third angle.

2 If one acute angle of a right triangle is half of the other, find both of

them.

3 The angles of a triangle are in the ratio 5:6:7.Find the angles.

4 The angles of a triangle are ( + 10)

0

, ( + 40)

0

and (2 −

30)

0

.Find the value of x and assign a special name to the triangle.

5 In an isosceles ΔABC, the measure of vertex angle A is 300 more

than the measure of each base angle. Find the measure of each angle

of the triangle.

6 One angle of a triangle is650

. Find the remaining two angles if their

difference is200

.

7 The sum of two angles of triangle is 800

and their difference is

200

.Find all the angles of a triangle.

8 If the angles of a triangle are ( + 40)

0

, (5 + 6)

0 &

(13 + 30)

0

, find the measure of all the angles.

9 In a triangle ABC, ∠A - ∠B =150

, ∠B - ∠C = 300

, Find the

measure of each angle of a triangle.

10 If each angle of a triangle is less than the sum of the other two,

then show that the triangle is acute angled.​

Answer 1

Answer:

nahi ho payega .ok .. vese try runga

Answer 2

Answer:

1. 180-(41+48)=180-89=91 is the third angle.

2. x+2x=90

   3x=90

   x=90/3

   x=30

3. 5x+6x+7x=18x=180

   x=180/18

   x=10

  angles are 50, 60 and 70