Physics, asked by purnasripodila, 6 hours ago

1)If we define a new system of units in which the unit of length is double that of present unit then the numerical value of μ0 (permeability of free space) will become
(A) half (B) double (C) unchanged (D) times

2)If the velocity of light denoted by ' c ' , acceleration due to gravity ' g ' and atmospheric pressure ' p ' are taken as fundamental units , then the dimensions of length will be :
(A) c^2/g (B) c/p (C) g/c (D) c/g

3)E , M , L , G denotes energy , mass , angular momentum (which is momentum x distance) and gravitational constant respectively EL^2 (M^5 G^2 ) . has the dimensions of :
(A) length (B) mass (C) angle (D) time

Answers

Answered by chandraprakashkulora
1

Answer:

Vacuum permeability is the magnetic permeability in a classical vacuum. Vacuum permeability is derived from production of a magnetic field by an electric current or by a moving electric charge and in all other formulas for magnetic-field production in a vacuum. Since the redefinition of SI units in 2019, the vacuum permeability μ0 is no longer a defined constant (per the former definition of the SI ampere), but rather needs to be determined experimentally.

The value in SI units, by CODATA 2018, is given below. It is simply proportional to the dimensionless fine-structure constant, with no other dependencies.[1][2][3]

μ0 = 1.25663706212(19)×10−6 H/m

Before this, in the reference medium of classical vacuum, μ0 had an exact defined value:[4][5]

μ0 = 4π×10−7 H/m = 1.2566370614…×10−6 N/A2 (1 henry per metre ≡ newton per square ampere)

The physical constant μ0, (pronounced "mu nought" or "mu zero") is commonly called the vacuum permeability. Alternatively it may be referred to as the permeability of free space, the permeability of vacuum, or the magnetic constant.

Explanation:

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