Question

1. If x=-1÷3 is a zero of the polynomial p(x) = 27x³ - ax²- x+3 , then find the value of a .

Answer 1

Hey mate ....

p(x) = 27(-1/3)^3 - a(-1/3)^2 -(-1/3) + 3

p(x) = -27/27 -a/9 +1/3+3=0

p(x) = 3 -a+3/9=0

p(x) = -a +27+3/9 = 0

p(x) = -a + 30/9 = 0

p(x) = -a = -10/3

therefore, x = 10/3...

hope its help you...

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