Question

1.If x-1 is a factor of mx2

-√2x+1, then the value of m is

Answer 1

Answer:

given, p(x) = mx^2 - √2x + 1

g(x) = x - 1

since x - 1 is a factor, then p(1) = 0

therefore p(1) = m(1)^2 - √2(1) + 1 = 0

=> m - √2 + 1 = 0

=> m = √2 - 1