Question

1. If x + 2y = 8, 2x + 3 z = 16 and 4y + 5z = 32,
then the value of x, y and z will be​

Answer 1

Answer:

x = 2

y = 3

z = 4

Step-by-step explanation:

x+2y = 8 (multiply it by 2)

We get

2x+4y = 16. eq 1

2x+3z = 16. eq 2

eq 1 - eq 2

We get 4y-3z=0. eq3

4y +5z = 32. eq4

eq3 - eq4

We get

- 8z = - 32

z=4.

Substitute value of z in eq3

We get

4y - 3(4) = 0

4y = 12

y = 3.

Substitute the vakue if y in eq1

2x +4(3) =16

2x +12 = 16

2x = 4

x=2