Question

1) If x=-5 is a root of the quadratic equation kx2 + 13X + 10 = 0,
to find the value of k​

Answer 1

kx²+13x+10

k. (-5)²+13.(-5)+10

k = 25-65+10

k= -30

Answer 2

Step-by-step explanation:

given x= -5

kx²+13x+10=0

k(-5)²+13(-5)+10=0

25k-65+10=0

25k-55=0

25k=55

k=55/25

k=11/5